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Post by stiltz on Aug 24, 2008 12:22:49 GMT -5
Hi I have just joined this forum because whilst googling the Internet I found a thread for one of main lines which includes the name Bohenna. So I decided to join up and see if I could be of help to the thread poster - however the thread was only running for a bit in Sept 2007 and I don't how how to go about letting this person know that I may have loads of info for them :(
Should I post onto the original thread or is it better for me to start a new one?
Thanks for any help - must say this forum looks fantastic!
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Post by myghaelangof on Aug 24, 2008 15:46:07 GMT -5
Hi Stiltz, Welcome to the forum. If you go the thread about Bohenna, look at the original entry to see who posted it. You can then click on their name (should be in blue or red) and you'll get info on the member. Some keep their email secret, others make it available. ;D You can also see when this member last logged on, to see if they are active. Whether active or not, its worth adding your own comments/interests as there are many helpful genealogists lurking about with the answer. Sometimes you just need to wait.....! Happy hunting, Mike
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Post by stiltz on Aug 26, 2008 9:46:11 GMT -5
Hi Mike
Thank you for your prompt reply to my question. Unfortunately the poster of the thread doesn't give an email address so I will do as you suggest and add a comment to the thread and wait and see if anything happens!
many thanks
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Post by Cornish Terrier on Aug 29, 2008 21:35:36 GMT -5
Hi Stiltz - as Mike suggested just post something to the relevant thread and you will get 'some bites'.
I will certainly take a look at it when I get to it but have a lot of catching up to do till that might happen.
However, I will be trying to at least have a brief glance at everything before I get down to a lot of the serious reply work.
I have an interest through a link with one of the Curnow lines and also, probably more particularly, the Behenna (name unknown) who married Elizabeth d/o Henry and Elizabeth Quick of Towednack.
Will catch up on the relevant board.
CT
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